help with 54mhz

[pico996969]

okay, my last 2 scenix chip i have no resonator's for so i'm wanting to do the 54mhz from the board.... i just need a little help painting the picture in my head of what goes where, and why?...the clock coming from the ps2 is 1.5v i think? this needs to be raised to 5v correct?...i see some chips that use crystals and OSC2 has no connection, but from a few posts i've seen i'm confused some say i do need to connect it and it needs to be 1/2 the voltage of OSC1, i'm using this on a v5 i have here, just wondering if anyone can help me out, and explain maybe step by step what i need connected...this is the diagram i'm using, if i'm too vague on what i need help with let me know

[pico996969]

sorry, this diagram

[Emanuel]

That's my diagram. The OSC_IN and OSC_54 are two solder points that you join for the chip to work and break apart when you want to reprogram the chip.
You connect the 54 MHz signal from the PS2 to the 54_IN point.

edit: You don't have to connect the OSC2 pin. The BFR transistor works as an amplifier. But because the hfe factor changes with temperature and from transistor to transistor, the amplification is not always the same. The SX28AC expects on the OSC1 pin a signal with 50% duty cycle. This signal is inverted inside the SX28AC and put on the OSC2 pin (still 50% duty cycle if it was so on the OCS1 pin). If the total amplification is too high or too low, the SX28AC will not receive a 50% duty cycle clock signal. To avoid this, you have to replace the 15K resistance with another value (10K-22K) and measure again the voltage at OSC2. This voltage is 2.5V if the SX28AC receives a 50% duty cycle clock signal.