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#1
Castlevania Symphony of the Night start with LV -50???
Castlevania Symphony of the Night start with LV -50??? –
07-11-2011,05:40 PM
Hi,Like captain america I just woke up and the first thing I want to do is play castlevania symphony of the night
BUT HARD MODE.
How can I use game shark to start at level negative 50 (-50)
I found these codes (however these are to make you start at level 99)
can anyone help me figure out these hex decimal numbers for -50 level
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Code Description
30097BB4 XXXX Modifies max MP of Alucard.
30097BA4 XXXX Modifies max HP
30097BAC XXXX Modifies max hearts.
30097BEC XXXX Modifies current experience.
30097BE8 XXXX Modifies current level.
To make it easier for you, here some random values. Replace the X's with:
Hex Decimal
0063 = 99
0EE7 = 999
270F = 9999
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07-16-2011,11:35 AM
FFCE.
Game will probably crash and/or show 65535. I don't thinks so that programist can permit that numbers.
Thank You for ask this question... :P I never before thinking about negative hexadecimal numbers, how to represent them and what is different between signed and unsigned.
Last edited by Berion; 07-16-2011 at 12:30 PM.
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07-21-2011,07:20 PM

Originally Posted by
Berion
FFCE.
Game will probably crash and/or show 65535. I don't thinks so that programist can permit that numbers.
Thank You for ask this question... :P I never before thinking about negative hexadecimal numbers, how to represent them and what is different between signed and unsigned.
Generally speaking the interpretation of signed binary numbers is based on the idea that all numbers having the top bit set are considered negative.
But in order for addition and subtraction of mixed positive and negative signed numbers to work properly this does not work out as a naive interpretation would have it.
So 0x8001 is NOT the correct negation value of 0x0001. That would instead be 0xFFFF... 
Say that we start with the absolute number 0xFFFF (decimal 65535).
Now if you add one to that number you get 0x10000 (decimal 65536), but in a 16 bit storage cell (whether CPU register of that size or just two bytes of RAM), it is impossible to store that kind of number, so the 'overflow' bit is just ignored. So in 16 bit arithmetic 0xFFFF + 0x0001 == 0x0000, and anything which gives a sum of zero when you add one to it must be considered a representation of minus one. This may all seem a bit oversimplified, but that is nevertheless how it really works.
Thus:
0xFFFF == -0x0001 == -1
0xFFFE == -0x0002 == -2
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0x8001 == -0x7FFF == -32767
0x8000 == -0x8000 == -32768 NB: The seeming contradiction in this line means that the positive value 32768 is impossible for a signed 16-bit number
The above allows a numerical range of -32768...+32767 for signed 16 bit numbers.
Translation of signed binary numbers to a wider word range is always possible, simply by extending copies of the top bit (the sign bit) into all the new top bits added.
Thus a 32-bit version of the 16-bit 0x8001 would be 0xFFFF8001 and this represents the negation of 0x00007FFF which is the 32-bit version of the 16-bit 0x7FFF.
As you can see, for positive numbers we simply inject a zero at the front, and for negative numbers we inject 'F' at the front, for each extended hex digit.
Floating point numbers are of course more complex, as the mantissa and the exponent are dealt with separately, and there are many different ways of doing this, even for the same word lengths. But nearly all methods do follow the basic patterns outlined above in their dealing with signs of both the mantissa and the exponent.
Best regards: dlanor
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08-03-2011,04:04 PM
Okay,
So I am at level 25 right now about half way into the game
how do I reset my level to 1?
using these codes
30097BE8 XXXX ( what do I put for the x's?)
Thanks.
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